Creative Commons License Copyright © Michael Richmond. This work is licensed under a Creative Commons License.

What is parallax?


What is parallax?

Parallax is the apparent shift in position of a nearby object when it is viewed from different locations. Those might be two different observatories on the Earth's surface (as was the case in the famous transits of Venus in the eighteenth and nineteenth centuries), but, in most astronomical applications, are two spots in Earth's orbit around the Sun:

If one knows the value of the baseline distance b, and can measure the parallax angle π

Yes, I know this is confusing. Yes, astronomers back in the old days should have picked a better letter. Sometimes you see the "curly pi" ϖ used to denote this angle, but few font families include it, so the parallax angle is usually written with the ordinary Greek letter π.

then one can use simple geometry to compute the distance to the target object d.



  Q:  Write a simple formula for d.



Of course, that simple formula ignores many complications. For example,

But one can work around these issues, or at least place constraints on their consequences.


Why is parallax such a good method?

The importance of parallax lies in its fundamental simplicity: we humans understand geometry, and trust it. As long as we can make measurements of the angular displacements over time, we can use the resulting distances with confidence.

There may be minor issues involving corrections for the small shifts of the background reference stars themselves; but if we choose to use galaxies or quasars as the reference sources, we can avoid those completely.

Most important of all, parallax is a direct method of measuring distances. It relies on a single assumed quantity: the astronomical unit (AU) = the distance from Earth to Sun. Back in the 1800s and early 1900s, this was indeed a major issue, and astronomers made great efforts to pin down the value of the AU. But these days, thanks to radar and spacecraft flying through the solar system, we do have a very, very good idea for the size of the AU. For example, the JPL Horizons system uses a value taken from the Planetary and Lunar Ephemerides DE430 and DE431, which list



       1 AU  = 149597870.700 km

That's ... quite a few signficant figures.

And that's it. Heliocentric parallax does NOT require any assumptions about stellar luminosity or evolution, or the distribution of sizes and colors of stars, or the spectral energy distribution of glowing hydrogen gas.

So, if astronomers can measure a distance via parallax, they will rely on it much more than distances determined by other methods.


An example: the parallax of an asteroid

In 2002, the asteroid 2002 NY40 flew past the Earth at a distance of less than one million kilometers. I used a telescope at the RIT Observatory in upstate New York to take its picture ...

... at exactly the same time that one of my colleagues at the Naval Academy in Annapolis, MD, did the same with her telescope:

If you compare the two images carefully, you should see that the background stars line up in the two images -- but the nearby asteroid clearly "jumps" from one image to the next due to parallax. (Click on the image below to blink the images).

 

We knew the distance between Rochester and Annapolis, and we could measure the size of the shift in the asteroid's position as seen from the two sites. With a little bit of geometry -- well, no, with quite a lot, actually -- we were able to calculate the distance to the asteroid.


Why is parallax so hard to measure?

It sounds as if using this technique to measure the distances to other stars should be pretty easy. In practice, though, it isn't quite so simple. There are a number of complications.

First, what exactly do we expect to see? As the Earth orbits the Sun, our point of view shifts back and forth, and so we ought to see nearby stars also shift back and forth, back and forth, relative to the distant ones. A simple, back-and-forth linear motion -- right?

Well, not quite. There's a complication due to the motion of our solar system and other stars in the Milky Way Galaxy. Even though most stars are circling the center of the Galaxy in the same general direction, each moves with a slightly different speed and direction. The result is that, over periods of decades and centuries and millenia, nearby stars appear to drift slowly across the sky. We call this proper motion.

The stars in the Big Dipper, which are relatively close to the Sun (only about 20-30 parsecs away), provide a dramatic illustration. Click on the picture below to watch a movie showing 200,000 years of proper motion.


Movie courtesy of Tony Dunn's proper motion simulator -- thanks, Tony!

So, if we make careful measurements of the position of a nearby stars over a period of several years, we expect to see it move in a path which combines

The result is something like a helix or corkscrew. You can see examples from the Hipparcos Intermediate Data archive by downloading and running their Java applet. The example below belongs to one of the brightest stars in the summer sky.


Thanks to the European Space Agency See also alternate version

You should be able to look at the diagram above and use the side-to-side shift to estimate the distance to this star. Can you do it?



  Q:  What is the amplitude of the side-to-side motion around 
              the diagonal straight line?  The units on both
              axes are milli-arcseconds.


  Q:  What is the amplitude of the parallax motion of this star,
              expressed in arcseconds?


  Q:  What is the distance to this star, expressed in parsecs?




My answers

By the way, do you know which star this is? The figure above provides its Right Ascension and Declination. If you were to type those coordinates into

perhaps you could identify it.


So why is it hard?

This seems relatively straightforward: take pictures of a nearby star 20 or 40 times over the course of several years, measure its position relative to distant stars carefully, fit a model consisting of some linear motion plus an elliptical component, and *poof* out pops the star's distance. What's so hard about that?

Well, I've neglected just one thing in this discussion so far: scale. Just how large are these motions? And how precisely can we measure the position of a star from a typical image?

Consider the image below, which shows the nearby star Ross 248. This is one of many CCD images I have acquired of this star with the 12-inch telescope at the RIT Observatory.

The target has a proper motion to the South, so if we were to measure it over a three-year period, we ought to see it move in a pattern like this:

Simple, right? Measure the size of the "wiggles" in its motion, and use them to determine the parallax angle, and thence the distance to the star. Done!









There just one little complication. In the picture above, I've drawn the motion of Ross 248 in a slightly exaggerated way so that it's easier for you to see. The real motion is a bit smaller ...

Because the motion has a small amplitude, it's not quite so easy to measure accurately. Still, with some care, this is still not a big deal, right?









Nope, I'm lying. I still haven't drawn the motion at its proper size. Let's zoom in a bit more.

Okay, NOW I've drawn the motion of Ross 248 at its proper scale. Over this 3-year period, the star will move about 4.8 arcseconds to the South. Since the pixels on the camera at the RIT Observatory subtend 1.25 arcseconds each, this corresponds to a motion of about 3.8 pixels.









Oh, but wait -- it's not the long axis of this motion that we want to measure -- it's the short axis, running roughly East-West, representing the shift due to the Earth's motion around the Sun. What we really want to measure is THIS motion:









Of course, the full side-to-side motion is TWICE the parallax angle, so we really need to figure out half of that shift. As you can read elsewhere, in order to use parallax to determine the distance to a star accurately, one must measure the parallax angle with an uncertainty of at most ten percent. In the figure below, the red square illustrates the precision to which we must find that angle.

Oh, and one more thing: this particular example, Ross 248, is one of the closest stars to our solar system: the ninth-closest stellar system, in fact. A more typical parallax measurement requires precision which is 10 times, or even 100 times, higher than this.

NOW you may start to understand why measuring the distances to stars is not so easy ....


Using distance to compute absolute magnitude

During the past decade, a European space telescope called Gaia has been measuring the parallaxes of millions and billions (literally) of stars in our Milky Way Galaxy. Thanks to its efforts, astronomers can now very easily look up the parallax to just about any star of interest.

Once we have the parallax π in arcseconds, we can compute the distance d in parsecs very easily:

Knowing the distance to a star allows us to start figuring out a number of its physical properties; its size, for example, or its luminosity, or perhaps its mass. When we measure the magnitude of a star in our sky by comparing its apparent brightness to that of stars in a catalog, we are finding its apparent magnitude, denoted by the lower-case letter m. A star which has a small apparent magnitude, and so appears bright to us, could be

Without the distance to the star, we can't tell the difference between stars in these two categories.

But once we DO know the distance, then we can use the following formula to calculate the absolute magnitude M (note the capital letter), which DOES tell us whether a star is feeble or powerful.

Let's do a calculation for practice.



  The bright star Vega has a parallax of 0.130 arcseconds,
  and an apparent magnitude m = 0.0.

         Q:  What is the distance to Vega, in parsecs?

         Q:  What is the absolute magnitude M of Vega?









My answers

The Sun is very close to the Earth, of course. It APPEARS to be very, very bright -- its apparent magnitude is m = -26.7. But how does it compare to other stars?



  The Sun is about 1.5 x 1011 meters from the Earth.
  One parsec is about 3.1 x 1016 meters.

         Q:  What is the distance to the Sun, in parsecs?

         Q:  What is the absolute magnitude M of the Sun?

         Q:  Is the Sun more or less powerful than Vega?









My answers


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Creative Commons License Copyright © Michael Richmond. This work is licensed under a Creative Commons License.