λ_{peak} = \frac{0.0029 m · K}{T}

e^{− \frac{hν}{kT}}  dominates when  hν > kT

E(n) = (Z^{2}) (−13.6 eV) (\frac{1}{n^{2}} )

E_{i} = KE = \frac{1}{2}(Nm_{H})v^{2}

E_{f} = KE + thermal E = \frac{1}{2}(Nm_{H}) (\frac{1}{4}v^{2}) + \frac{3}{2}kT (N + 10N)

T = ( \frac{\frac{15}{16} m_{H} v^{2}}{33 k} )