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Question 1
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Electric field is E = (3, 0, 0) N/C everywhere. What is the potential difference V(B) - V(A) if

A = (1, 1, 1) m B = (2, 2, 2) m

Answer: To find the potential difference, integrate the electric field over a path from A to B: B / V(B) - V(A) = - | E dot ds / A Recall that 3 N/C = 3 V/m. = - E * x evalulated from A to B = - [ (3 V/m * 2 m) - (3 V/m * 1 m) ] = - [ 6 V/m - 3 V/m ] = - 3 Volts

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Question 2
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Electric potential is V = 6 Volts everywhere. What is the electric field at point A = (1, 1, 1) m?

Answer: Electric field is gradient of electric potential Ex = dV/dx = 0 Ey = dV/dy = 0 Ez = dV/dz = 0

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Question 3
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Electric field of strength 6 N/C can be written equivalently as ...

Answer: 6 V/m, because 1 Newton/Coulomb is the same as 1 Volt/meter

Copyright © Michael Richmond. This work is licensed under a Creative Commons License.