A particle of dust of mass m = 2 x 10^(-3) kg has an initial speed v = 2 m/s.
An electric field inside the lab exerts a force
F = 12 mN i - 6 mN j + 8 mN k
on a small dust particle. As the particle moves through the room, its location changes from
initial pos r1 = 1.2 m i + 0.3 m j + 0.6 m kto
final pos r2 = 3.5 m i - 1.2 m j - 0.1 m k
Copyright © Michael Richmond. This work is licensed under a Creative Commons License.