Barnard's Star is a low-mass dwarf on the main sequence which happens to be relatively close to our solar system. Assume that its mass is about 0.16 solar masses. 1. what is the apparent magnitude of Barnard's Star? apparent V mag = 9.54 2. what is the distance to Barnard's Star? Hipparcos finds parallax = 549.3 milliarcseconds -> distance = 1/0.5493 = 1.82 pc 3. what is the absolute magnitude of Barnard's Star? (m - M) = 5 log d - 5 M = m + 5 - 5 log d = 9.54 + 5 - 5 log(1.82) = 14.54 - 1.30 = 13.24 4. what is the luminosity of Barnard's Star? If a star has absolute V-band magnitude M, then its luminosity is roughly 28 -0.4 * M L = 3 x 10 W * 10 28 -6 = 3 x 10 W * 5.06 x 10 = 1.5 x 10^(23) W The Sun produces about 3.8 x 10^(26) W, so Barnard's star has a luminosity of only about 0.0004 solar. 5. if Barnard's star were pure hydrogen at birth, and maintained its current luminosity, roughly how long could it remain on the main sequence? Use its initial mass, its luminosity, and the efficiency of hydrogen fusion to make your estimate. Barnard's star produces 1.5 x 10^(23) Watts, or 1.5 x 10^(23) Joules each second. We know that fusion of 4 hydrogen atoms requires 6.69 x 10^(-27) kg and generates 4.3 x 10^(-12) Joules. So we can figure out how many kg of hydrogen Barnard's star must fuse each second. 6.69 x 10^(-27) kg 4.3 x 10^(-12) J -------------------- = -------------------- X kg 1.5 x 10^(23) J Solve for X, the number of kg which must be fused each second: X kg = 2.36 x 10^(8) kg Now, if Barnard's star has a mass of 0.16 solar, and if it was all pure hydrogen at birth, then it started with mass = 0.16 * 2 x 10^(30) kg mass = 3.2 x 10^(29) kg We can calculate how long it would last if it fused X kg each second: starting mass lifetime = ------------------- rate of using mass 3.2 x 10^(29) kg = ------------------- 2.36 x 10^(8) kg/s = 1.4 x 10^(21) seconds = 43,000 billion years 2. Look at the figure at the link below, showing the expanding shell around SN 1993J. Calculate the speed with which gas was ejected in the supernova explosion. My trusty ruler shows that 1993 May 17 radius = 220 AU JD = 2,449,125 1997 Jun 7 radius = 11,000 AU JD = 2,450,607 ------------------------------------------------------ 10,880 AU 1,482 So the shell was expanding at a rate of 10,880 AU 8.5 x 10^(-5) AU avg speed = ---------- = ---------------- 1,482 days second = 13,000 km/sec