Q:  What is the moment of inertia of the rod-plus-putty
            around the pivot?

            I  =  (1/3) * M * L^2   +  m * L^2

               =     0.96 kg*m^2    +   0.576 kg*m^2

               =     1.54 kg*m^2



  Q:  What is the angular velocity of the rod-plus-putty object?

           L   =   I * omega   =  L(before)  =  2.88 kg*m^2/s

                         2.88 kg*m^2/s
        -->   omega  =  ---------------
                          1.54 kg*m^2


                     =   1.88 rad/s