In the picture, we can estimate

         Harold Lloyd     is an adult human        mass   m = 60 kg

         radius vector from axis to Lloyd        radius   R = 1 m

         time is 2:42 PM

  The torque will be given by 

             
           tau  =   r  *  F  *  sin(theta)

  where

             r    =     1 m      at angle of 18 degrees below horizontal

             F    =    m * g  =  (60 kg) * (9.8 m/s^2)  

                  =   588 N      at angle 90 degrees below vertical


  so      theta   =   (90 - 18)  =  72 degrees


  Therefore, the size of the torque is


           tau  =   1 m  *  588 N  *  sin(72 deg)   =   559 N*m


  The direction of the torque is  OUT of the clock's face.