\magnification=\magstep1


$$
P_{ast} \quad = \quad {{1}\over{2}} P_J
$$

$$
a_{ast} \quad = \quad {(P_{ast})}^{2/3}
$$

$$
a_{ast} \quad = \quad {(11.9 / 2)}^{2/3}
$$

$$
{\rm KE} \quad = \quad {{1}\over{2}} \ m v^2
$$

$$
a \quad = \quad {(P)}^{2/3}
$$
\bye
