Q:  What is the energy of a ground state, n=1, in this atom?
 
                                    2      (  1  ) 2
           E   =  (-13.6 eV) *  (26)    *  (-----)
            n                              (  n  )
 

           E1  =  -9194 eV
            

  Q:  What is the energy of the n=2 state in this atom?

           E2  =  -2298 eV


  Q:  What is the energy emitted when this atom jumps from n=2 to n=1?

           E2 - E1  =  6896 eV     ->   lambda = 0.18 nm